Solution 7bbb8c48-711b-4cbe-b6e3-c2aed29c9127

Points: 

Factoring out $7!$, we get
\[
10!-7!6!=7!\bigl(10\cdot9\cdot8-6!\bigr).
\]
Prime factorizing and regrouping,
\[
\begin{aligned}
10\cdot9\cdot8
&=(2\cdot5)\cdot3^2\cdot2^3\\
&=2^4\cdot3^2\cdot5\\
&=1\cdot2\cdot3\cdot4\cdot5\cdot6=6!.
\end{aligned}
\]
Hence,
\[
10!-7!6!=7!(6!-6!)=0.
\]

Final answer:
0