Solution 9152d5ae-353b-4c66-b343-84c362120535

Points: 1 pt

We can draw a number line and count.

\begin{tikzpicture}[x=0.72cm,y=0.72cm,>=Stealth]
  % Number line
  \draw[->, line width=0.7pt] (-5.65,0) -- (10.65,0);

  % Tick marks and labels
  \foreach \x in {-5,-4,...,10} {
    \draw[line width=0.65pt] (\x,0.12) -- (\x,-0.12);
    \node[below=3pt, font=\scriptsize] at (\x,0) {$\x$};
  }

  % Hop from 0 to 5
  \draw[->, line width=1.1pt]
    (0,0.18) .. controls (1.2,0.68) and (3.8,0.68) .. (5,0.18);
  \node[font=\small\bfseries] at (2.5,0.80) {$+5$};

  % Hop backward 7 from 5 to -2
  \draw[->, line width=1.1pt]
    (5,0.28) .. controls (3.3,1.92) and (-0.3,1.92) .. (-2,0.28);
  \node[font=\small\bfseries] at (1.5,1.92) {$-7$};

  % Emphasize the landing points
  \fill (0,0) circle (1.5pt);
  \fill (5,0) circle (1.5pt);
  \fill (-2,0) circle (1.5pt);
\end{tikzpicture}

We see that counting forward $5$ and backward $7$ makes us land at $-2$.

Final answer:
-2