Solution 9687a1c3-dddf-437e-b654-f43d3d3ce11a

Points: 1 pt

We use long division:

\LongDivisionTenByThree

Since
\[
10 = (3)(3) + 1,
\]
the quotient is $3$ and the remainder is $1$. This result is in agreement with the division algorithm because
\[
10 \geq 3 > 1,
\]
as required.

Final answer:
10 \div 3 = 3\text{ R }1

Notation definitions (retained for meaning):
\newcommand{\LongDivisionTenByThree}{\begin{center}
\begin{tikzpicture}[
  x=10mm,
  y=7.4mm,
  every node/.style={font=\rmfamily\large, inner sep=0pt, outer sep=0pt}
]
  % quotient
  \node at (3.1,0.95) {$3$};
  % division bracket
  \draw[line width=0.65pt] (1.55,0.45) -- (4.55,0.45);
  \draw[line width=0.65pt] (1.55,0.45) -- (1.55,-0.45);

  % divisor and dividend
  \node at (0.85,0) {$3$};
  \node at (3.1,0) {$10$};

  % subtraction step
  \draw[line width=0.55pt] (1.75,-1.10) -- (2.05,-1.10);
  \node at (3.1,-1.10) {$9$};
  \draw[line width=0.45pt] (2.35,-1.52) -- (3.85,-1.52);

  % remainder
  \node at (3.1,-2.35) {$1$};
\end{tikzpicture}
\end{center}
}